Question
Simplify $: − 64x^4y^3z \div 4x^3y^2z$

Answer

$-64 x^4 y^3 z \div 4 x^3 y^2 z$
$=\frac{4 \times 4 \times 4 \times x^4 \times y^3 \times z}{4 \times x^3 \times y^2 \times z}$
$=-16 x^{4-3} \times y^{3-2}$
$=-16 x y$

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