Question
Simplify: $\frac{-65}{14}\div\frac{13}{7}$
✓
Answer
$\frac{-65}{14}\div\frac{13}{7}$
$\frac{-65}{14}\times\frac{7}{13}$
$=\frac{-455}{182}$
$=\frac{-455\div91}{182\div91}$
$=\frac{-5}{2}$
$\frac{-65}{14}\times\frac{7}{13}$
$=\frac{-455}{182}$
$=\frac{-455\div91}{182\div91}$
$=\frac{-5}{2}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Find the area of quadrilateral $PQRS$ shown in Fig.
→Subtract the first rational number from the second in the following: $\frac{-2}{11},\frac{-9}{11}$
→Using suitable rearrangement and find the sum: $-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\frac{-4}{5}$
→Replace $A, B, C$ by suitable numerals.
→Subtract: $\frac{-32}{13}\ \text{from}\ \frac{-6}{5}$
→Find the angle measure $x$ in this figure.
→The area of a trapezium shaped field is $480$ $m^2$, the distance between two parallel sides is $15\ m$ and one of the parallel side is $20\ m$. Find the other parallel side.
→Two adjacent angles of a parallelogram have equal measure. Find the measure of each of the angles of the parallelogram.
For an experiment in Botany, two different plants, plant $A$ and plant $B$ were grown under similar laboratory condition. Their heights were measured at the end of each week for $3$ weeks. The results are shown in the graph. How high was Plant $B$ after $(i) 2$ weeks $(ii) 3$ weeks?
→Solve the equation and check your result: $3x = 2x + 18$
→