Question
Simplify: $7\frac{5}{6}-4\frac{3}{8}+2\frac{7}{12}$
✓
Answer
We have, $7\frac{5}{6}-4\frac{3}{8}+2\frac{7}{12}$
$=\frac{47}{6}-\frac{35}{8}+\frac{31}{12}$
Taking out the $LCM$ of $6, 8$ and $12$ we get, $2 \times 2 \times 2 \times 3 = 48$
Now, we convert the given fractions to equivalent fraction by making the denominators $48$
we get, $\frac{47\times8}{6\times8}-\frac{35\times6}{8\times6}+\frac{31\times4}{12\times4}$
$=\frac{376}{48}-\frac{210}{48}+\frac{124}{48}$
$=\frac{376-210+124}{48}$
$=\frac{290}{48}$
$=\frac{145}{24}$
$=\frac{47}{6}-\frac{35}{8}+\frac{31}{12}$
Taking out the $LCM$ of $6, 8$ and $12$ we get, $2 \times 2 \times 2 \times 3 = 48$
Now, we convert the given fractions to equivalent fraction by making the denominators $48$
we get, $\frac{47\times8}{6\times8}-\frac{35\times6}{8\times6}+\frac{31\times4}{12\times4}$
$=\frac{376}{48}-\frac{210}{48}+\frac{124}{48}$
$=\frac{376-210+124}{48}$
$=\frac{290}{48}$
$=\frac{145}{24}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Social Studies Application: Remembering that $1AD$ came immediately after $1BC,$ while solving these problems take $1BC$ as $-1$ and $1AD$ as $+1.$ Bhaskaracharya was born in the year $1114AD$ and died in the year $1185AD.$ What was his age when he died$?$
→Determine whether the triangles are congruent. If yes, express the congruence.
Draw the number line and represent the following rational number on it:
$\frac{3}{4}$
→$\frac{3}{4}$
Simplify:$\frac{8}{9}\div16$
→ Find the following product:
$\frac{7}{2}\text{x}^2\Big(\frac{4}{7}\text{x}+2\Big)$
→$\frac{7}{2}\text{x}^2\Big(\frac{4}{7}\text{x}+2\Big)$
From a circular sheet of radius 4 cm , a circle of radius 3 cm is removed. Find the area of the remaining sheet. (take $\pi=3.14$ )
→Find the area of a parallelogram with base $32\ cm$ and height $16.5\ cm.$
→Divide: $0.768$ by $16$
→Find the value of $x,$ if: $32\%$ of $x\ kg$ is $400\ kg.$
→Add and express the sum as a mixed fraction:
$\frac{24}{7}+\frac{-11}{4}$
→$\frac{24}{7}+\frac{-11}{4}$