Question
Simplify:
$7\frac{5}{6}-4\frac{3}{8}+2\frac{7}{12}$

Answer

We have,
$7\frac{5}{6}-4\frac{3}{8}+2\frac{7}{12}$
$=\frac{47}{6}-\frac{35}{8}+\frac{31}{12}$
Taking out the LCM of 6, 8 and 12 we get,
2 × 2 × 2 × 3 = 48
Now, we convert the given fractions to equivalent fraction by making the denominators 48 we get,
$\frac{47\times8}{6\times8}-\frac{35\times6}{8\times6}+\frac{31\times4}{12\times4}$
$=\frac{376}{48}-\frac{210}{48}+\frac{124}{48}$
$=\frac{376-210+124}{48}$
$=\frac{290}{48}$
$=\frac{145}{24}$

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