Question
Simplify:
$\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$
$\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$
✓
Answer
$\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$ $$LCM of 11, 3, 4 = 11 × 3 × 4 = 132 $\therefore\frac{-9}{11}=\frac{-9\times12}{11\times12}=\frac{-108}{132}$ $\frac{2}{3}=\frac{2\times44}{3\times44}=\frac{88}{132}$ $\frac{-3}{4}=\frac{-3\times33}{4\times33}=\frac{-99}{132}$ $\therefore\frac{-9}{11}+\frac{2}{3}+\frac{-3}{4}$ $=\frac{-108}{132}+\frac{88}{132}+\frac{-99}{132}$ $=\frac{-108+88+(-99)}{132}$ $=\frac{-108+88-99}{132}$ $=\frac{-207+88}{132}$$=\frac{-119}{132}$
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