Question
Simplify:
$\frac{-9}{8}\times\frac{-16}{3}$
$\frac{-9}{8}\times\frac{-16}{3}$
✓
Answer
$\frac{-9}{8}\times\frac{-16}{3}$
$=\frac{(-9)\times(-16)}{8\times3}$
$=\frac{(-3)\times(-2)}{1\times1}$
$=\frac{6}{1}=6$
$=\frac{(-9)\times(-16)}{8\times3}$
$=\frac{(-3)\times(-2)}{1\times1}$
$=\frac{6}{1}=6$
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