Question
Simplify:
$(a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)$
$(a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)$
✓
Answer
We have:
$(a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)$
$= a^2 + b^2 + 2ab - a^2 - b^2 + 2ab$
$= a^2 - a^2 + b^2 - b^2 + 2ab + 2ab$
$= 0 + 0 + (2 + 2)ab$
$= 4ab$
$(a^2 + b^2 + 2ab) - (a^2 + b^2 - 2ab)$
$= a^2 + b^2 + 2ab - a^2 - b^2 + 2ab$
$= a^2 - a^2 + b^2 - b^2 + 2ab + 2ab$
$= 0 + 0 + (2 + 2)ab$
$= 4ab$
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