Question
Simplify and express each as a rational number:
$\Big(\frac{4}{9}\Big)^6\times\Big(\frac{4}{9}\Big)^{-4}$

Answer

$\Big(\frac{4}{9}\Big)^6\times\Big(\frac{4}{9}\Big)^{-4}$
$=\Big(\frac{4}{9}\Big)^{6-4}=\Big(\frac{4}{9}\Big)^2$
$=\frac{4}{9}\times\frac{4}{9}=\frac{16}{81}$

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