Question
Simplify and express the number in exponential form: $\frac{4^{5} \times a^{8} b^{3}}{4^{5} \times a^{5} b^{2}}$
✓
Answer
By the law of exponents, we have
$\frac{X^m}{X^n}=X^{m-n} \text { and } a^{\circ}=1$
By applying the law of exponents we have
$\frac{4^5}{4^5} \times \frac{a^8}{a^5} \times \frac{b^3}{b^2}=4^{5-5} \times a^{8-5} \times b^{3-2}$
$\frac{4^5 \times a^8 b^3}{4^5 \times a^5 b^2}=4^0 \times a^3 \mathrm{~b}=a^3 \mathrm{~b}$
$\frac{X^m}{X^n}=X^{m-n} \text { and } a^{\circ}=1$
By applying the law of exponents we have
$\frac{4^5}{4^5} \times \frac{a^8}{a^5} \times \frac{b^3}{b^2}=4^{5-5} \times a^{8-5} \times b^{3-2}$
$\frac{4^5 \times a^8 b^3}{4^5 \times a^5 b^2}=4^0 \times a^3 \mathrm{~b}=a^3 \mathrm{~b}$
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