Question
Simplify and solve the linear equation: $3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17$
✓
Answer
$3(5z – 7) – 2(9z – 11) = 4(8z – 13) – 17$
$\therefore 15z – 21 – 18z + 22 = 32z – 52 – 17$
$\therefore – 3z + 1 = 32z – 69$
$\therefore –3z + 32z = –69 – 1 ... [$Transposing $32z$ to $L.H.S.$ and $1$ to $R.H.S.]$
$\therefore –35z = – 70$
$\therefore z = \frac{{ - 70}}{{ - 35}} ... [$Dividing both sides by $–35]$
$\therefore z = 2$ this is the required solution.
$\therefore 15z – 21 – 18z + 22 = 32z – 52 – 17$
$\therefore – 3z + 1 = 32z – 69$
$\therefore –3z + 32z = –69 – 1 ... [$Transposing $32z$ to $L.H.S.$ and $1$ to $R.H.S.]$
$\therefore –35z = – 70$
$\therefore z = \frac{{ - 70}}{{ - 35}} ... [$Dividing both sides by $–35]$
$\therefore z = 2$ this is the required solution.
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