Question
Simplify: $\Big(\frac{-3}{2}\Big)^{3}\div\Big(\frac{-3}{2}\Big)^{6}$

Answer

$\Big(\frac{-3}{2}\Big)^{3}\div\Big(\frac{-3}{2}\Big)^{6}$ $=\Big(\frac{-3}{2}\Big)^{3-6}=\Big(\frac{-3}{2}\Big)^{-3}$ $=\Big(\frac{-2}{3}\Big)^3=\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}$ $=\frac{-8}{27}$

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