Question
Simplify: $\Big(\frac{32}{243}\Big)^{-\frac{4}{5}}$
✓
Answer
$\Big(\frac{32}{243}\Big)^{-\frac{4}{5}}$ $=\Big(\frac{243}{32}\Big)^{\frac{4}{5}}$ $=\Big(\frac{3^5}{2^5}\Big)^{\frac{4}{5}}$ $=\frac{3^{5\times\frac{4}{5}}}{2^{5\times\frac{4}{5}}}$ $=\frac{3^4}{2^4}$ $=\frac{81}{16}$
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