Question
Simplify: $\Big(\frac{81}{49}\Big)^{-\frac{3}{2}}$

Answer

$\Big(\frac{81}{49}\Big)^{-\frac{3}{2}}$ $=\Big(\frac{49}{81}\Big)^{\frac{3}{2}}$ $=\Big(\frac{7^2}{9^2}\Big)^{\frac{3}{2}}$ $=\frac{7^{2\times\frac{3}{2}}}{9^{2\times\frac{3}{2}}}$ $=\frac{7^3}{9^3}$ $=\frac{343}{729}$

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