Question
Simplify:
$\bigg\{\Big(\frac{-2}{3}\Big)^2\bigg\}^3$
$\bigg\{\Big(\frac{-2}{3}\Big)^2\bigg\}^3$
✓
Answer
$\bigg\{\Big(\frac{-2}{3}\Big)^2\bigg\}^3$
$=\Big(\frac{-2}{3}\Big)^{2\times3}=\Big(\frac{-2}{3}\Big)^6$
$=\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}$
$=\frac{64}{729}$
$=\Big(\frac{-2}{3}\Big)^{2\times3}=\Big(\frac{-2}{3}\Big)^6$
$=\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}\times\frac{-2}{3}$
$=\frac{64}{729}$
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