Question
Simplify:
$\bigg\{\Big( \frac{1}{2}\Big )^{-1}\times(-4)^{-1}\bigg\}$

Answer

$\bigg\{\Big( \frac{1}{2}\Big )^{-1}\times(-4)^{-1}\bigg\}$
$=\bigg\{\Big(2)^1\times\Big(\frac{1}{-4}\Big)^1\bigg\}=\Big(2\times\frac{1}{-4}\Big)^{-1}$
$=\Big(\frac{-1}{2}\Big)^{-1}=(-2)^1=-2$

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