Question
Simplify:
$\Bigg[\bigg\{\Big(\frac{-1}{4}\Big)^2\bigg\}^{-2}\Bigg]^{-1}$

Answer

$\Bigg[\bigg\{\Big(\frac{-1}{4}\Big)^2\bigg\}^{-2}\Bigg]^{-1}=\Bigg[\Big(\frac{-1}{4}\Big)^{2\times(-2)}\Bigg]^{-1}$
$=\bigg[\Big(\frac{-1}{4}\Big)^{-4}\bigg]^{-1}$
$=\Big(\frac{-1}{4}\Big)^{-4\times(-1)}=\Big(\frac{-1}{4}\Big)^{4}$
$=\frac{-1}{4}\times\frac{-1}{4}\times\frac{-1}{4}\times\frac{-1}{4}$
$=\frac{1}{256}$

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