Given,$\frac{3}{7}÷\left(\frac{21}{-55}\right)$ The reciprocal of $\frac{21}{-55}$ is $\frac{-55}{21}$ So, $\frac{3}{7} \times \frac{(-55)}{21}=\frac{(-55) \times 3}{7 \times 21}=\frac{-55}{49}$
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