Question
Simplify: $\frac{6}{5}$ of $\left(3 \frac{1}{3}-2 \frac{1}{2}\right)+\left(2 \frac{5}{21}-2\right)$

Answer


$\begin{aligned} & \frac{6}{5} \text { of }\left(3 \frac{1}{3}-2 \frac{1}{2}\right) \div\left(2 \frac{5}{21}-2\right) \\ & =\frac{6}{5} \text { of }\left(\frac{10}{3}-\frac{5}{2}\right) \div\left(\frac{47}{21}-\frac{2}{1}\right) \ldots(\text { Using BODMAS }) \\ & =\frac{6}{5} \text { of }\left(\frac{20-15}{6}\right) \div\left(\frac{47-42}{21}\right) \\ & =\frac{6}{5} \text { of } \frac{5}{6} \div \frac{5}{21} \\ & =1 \div \frac{5}{21} \\ & =1 \times \frac{21}{5}=\frac{21}{5}=4 \frac{1}{5}\end{aligned}$

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