Question
Simplify: $\frac{6 \mathrm{k}}{7}-\left(\frac{8 \mathrm{k}}{9}-\frac{\mathrm{k}}{3}\right)$

Answer


$\begin{aligned} & \frac{6 \mathrm{k}}{7}-\left(\frac{8 \mathrm{k}}{9}-\frac{\mathrm{k}}{3}\right) \\ & =\frac{54 \mathrm{k}-(56 \mathrm{k}-21 \mathrm{k})}{63} \quad \ldots(\mathrm{LCM} \text { of } 7,9,3=63) \\ & =\frac{54 \mathrm{k}-(35 \mathrm{k})}{63} \\ & =\frac{54 \mathrm{k}-35 \mathrm{k}}{63}=\frac{19 \mathrm{k}}{63}\end{aligned}$

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