Question
Simplify, giving Solution with positive index
$4x^2y^2 ÷ 9x^3y^3$​​​​​​​

Answer

$4 x^2 y^2 \div 9 x^3 y^3$
$=\frac{4 x^2 y^2}{9 x^3 y^3}=\frac{4 x^{2-3} y^{2-3}}{9}$
$=\frac{4 x^{-1} y^{-1}}{9}=\frac{4}{9 x y}$ (Since index should by positive)

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