Question
Simplify, giving Solution with positive index
$(n^2)^2 (- n^2)^2$​​​​​​​

Answer

$ \left(n^2\right)^2\left(-n^2\right)^2$
$ =n^{2 \times 2}(-n)^{2 \times 3}=n^4 \times(-n)^6$
$ =-n^4-1^6 n^6 $
$ =-n^{4+6}=-n^{10}$

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