Indices — Maths STD 7 — Question

\begin{aligned}
& \left(-\frac{3}{2}\right)^5 \times\left(-\frac{3}{2}\right)^3 \\
& =\left(-\frac{3}{2}\right)^{5+3}=\left(-\frac{3}{2}\right)^8
\end{aligned}