Question
Simplify $\frac{\left(2^{5}\right)^{2} \times 7^{3}}{8^{3} \times 7}$

Answer

$\frac{\left(2^{5}\right)^{2} \times 7^{3}}{8^{3} \times 7}=\frac{2^{5 \times 2} \times 7^{3}}{\left(2^{3}\right)^{3} \times 7}=\frac{2^{10} \times 7^{3}}{2^{3 \times 3} \times 7}$
= $\frac{2^{10} \times 7^{3}}{2^{9} \times 7}$
$=2^{10-9} \times 7^{3-1}=2^{1 \times 7^2}$
$=2 \times 7 \times 7=98$

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