Question
Simplify: $\left(\frac{5}{8}\right)^{-7} \times\left(\frac{8}{5}\right)^{-5}$
✓
Answer
$\left(\frac{5}{8}\right)^{-7} \times\left(\frac{8}{5}\right)^{-5}$ = $\frac{5^{-7}}{8^{-7}} \times \frac{8^{-5}}{5^{-5}}=\frac{5^{-7}}{5^{-5}} \times \frac{8^{-5}}{8^{-7}}$
= $5^{(-7)-(-5)} \times 8^{(-5)-(-7)}$ = $5^{-2} \times 8^{2}=\frac{8^{2}}{5^{2}}=\frac{64}{25}$
= $5^{(-7)-(-5)} \times 8^{(-5)-(-7)}$ = $5^{-2} \times 8^{2}=\frac{8^{2}}{5^{2}}=\frac{64}{25}$
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