Question
Simplify$: \log a^2 + \log a^{-1}$
✓
Answer
$\log a^2 + \log a^{-1}$
$= 2 \log a + (-1) \log a$
$= 2 \log a - \log a$
$= \log a (2 - 1)$
$= \log a.$
$= 2 \log a + (-1) \log a$
$= 2 \log a - \log a$
$= \log a (2 - 1)$
$= \log a.$
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