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Exponents Of Real Numbers — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsExponents Of Real Numbers2 Marks
Question
Simplify:$\sqrt[5]{(32)^{-3}}$
✓

Answer

We have,$\sqrt[5]{(32)^{-3}}=[(32)^{-1}]^{\frac{1}{5}}$
$=[(2^5)^{-3}]^\frac{1}{5}$
$=2^{5\times(-3)\times\frac{1}{5}}$
$=2^{-3}$
$=\frac{1}{2^3}$
$=\frac{1}{8}$

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