Question
Simplify: $\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
✓
Answer
Removing the innermost grouping symbol ‘—’ first, then $( )$, then $\{ \}$ and then $[ ]$,
we have: $\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
$= 2a - [4b - {4a - (3b - 2a - 2b)}] $
$= 2a - [4b - {4a - (b - 2a)}] $
$= 2a - [4b - {4a - b + 2a}] $
$= 2a - [4b - {6a - b}] $
$= 2a - [4b - 6a + b] $
$= 2a - [5b - 6a] $
$= 2a - 5b + 6a $
$= 8a - 5b.$
we have: $\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
$= 2a - [4b - {4a - (3b - 2a - 2b)}] $
$= 2a - [4b - {4a - (b - 2a)}] $
$= 2a - [4b - {4a - b + 2a}] $
$= 2a - [4b - {6a - b}] $
$= 2a - [4b - 6a + b] $
$= 2a - [5b - 6a] $
$= 2a - 5b + 6a $
$= 8a - 5b.$
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