Question
Simplify:
$\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
$\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
✓
Answer
Removing the innermost grouping symbol ‘—’ first, then ( ), then { } and then [ ], we have:
$\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
= 2a - [4b - {4a - (3b - 2a - 2b)}]
= 2a - [4b - {4a - (b - 2a)}]
= 2a - [4b - {4a - b + 2a}]
= 2a - [4b - {6a - b}]
= 2a - [4b - 6a + b]
= 2a - [5b - 6a]
= 2a - 5b + 6a
= 8a - 5b.
$\text{2a}-[4\text{b}-\{\text{4a}-(3\text{b}-\overline{2\text{a}+2\text{b}})\}]$
= 2a - [4b - {4a - (3b - 2a - 2b)}]
= 2a - [4b - {4a - (b - 2a)}]
= 2a - [4b - {4a - b + 2a}]
= 2a - [4b - {6a - b}]
= 2a - [4b - 6a + b]
= 2a - [5b - 6a]
= 2a - 5b + 6a
= 8a - 5b.
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