Question
Simplify the exponential form: $\frac{1}{8} \times(3)^{-3}$

Answer

$\frac{1}{8} \times(3)^{-3}$
= $\frac{1}{2^{3}} \times(3)^{-3}=2^{-3} \times 3^{-3}$
= $(2 \times 3)^{-3}=6^{-3}=\frac{1}{6^{3}}$

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