Question
Simplify the expression $2\left(a^2+a b\right)+3-a b$ and find its value when $a = 5$ and $b = –3$
✓
Answer
$=2 a^2+2 a b+3-a b$
$=2 a^2+2 a b-a b+3 \ldots[\text { rearranging terms }]$
$=2 a^2+a b+3$
when $a=5, b=-3$ then
$=2(5)^2+(5)(-3)+3$
$=50-15+3$
$=50+3-15$
$=53-15$
$=38$
$=2 a^2+2 a b-a b+3 \ldots[\text { rearranging terms }]$
$=2 a^2+a b+3$
when $a=5, b=-3$ then
$=2(5)^2+(5)(-3)+3$
$=50-15+3$
$=50+3-15$
$=53-15$
$=38$
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