Question
Simplify the following:
$25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}$
$25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}$
✓
Answer
$25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}$
$=25-\frac{1}{2}\big[5+4-(5-4)\big]$
$=25-\frac{1}{2}\big[5+4-1\big]$
$=25-\frac{1}{2}[8]$
$=25-4$
$=21$
$\therefore25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}=21$
$=25-\frac{1}{2}\big[5+4-(5-4)\big]$
$=25-\frac{1}{2}\big[5+4-1\big]$
$=25-\frac{1}{2}[8]$
$=25-4$
$=21$
$\therefore25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}=21$
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