Question
Simplify the following: $\frac{2\sqrt{3}}{3}-\frac{\sqrt{3}}{6}$

Answer

$\frac{2\sqrt{3}}{3}-\frac{\sqrt{3}}{6}$ $=\sqrt{3}\Big(\frac{2}{3}-\frac{1}6{}\Big)=\sqrt{3}\Big(\frac{4-1}{6}\Big)$ $\sqrt{3}\times\frac{3}{6}=\frac{\sqrt{3}}{2}$

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