Question
Simplify the following:
$\left(2 x^{-2} y^3\right)^3$
$\left(2 x^{-2} y^3\right)^3$
✓
Answer
$\left(2 x^{-2} y^3\right)^3$
$\left(2^3 \times x^{-2} \times 3 y^{3 \times 3}\right)=8 x^{-6} y^9$
$\left(2^3 \times x^{-2} \times 3 y^{3 \times 3}\right)=8 x^{-6} y^9$
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