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Integers — Maths STD 7 — Question

Maharashtra BoardEnglish MediumSTD 7MathsIntegers3 Marks
Question
Simplify the following:
$36-\big[18-\{14-(15-4\div2\times2)\}\big]$
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Answer

$36-\big[18-\{14-(15-4\div2\times2)\}\big]$
$=36-\big[18-\{14-(11\div2\times2)\}\big]$
$=36-\Big[18-\Big\{14-\Big(\frac{11}{2}\times2\Big)\Big\}\Big]$
$=36-\big[18-\big\{14-11\big\}\big]$
$=36-\big[18-3\big]$
$=36-15$
$=21$
$\therefore\ 36-\big[18-\{14-(15-4\div2\times2)\}\big]=21$

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