Question
Simplify the following: $\frac{3}{\sqrt{8}}+\frac{1}{\sqrt{2}}$
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Answer
$\frac{3}{\sqrt{8}}+\frac{1}{\sqrt{2}}$ $=\frac{3}{\sqrt{4\times2}}+\frac{1}{\sqrt{2}}=\frac{1}{\sqrt{2}}\Big(\frac{3}{2}+1\Big)$ $=\frac{5}{2\sqrt{2}}=\frac{5}{2\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}=\frac{5\sqrt{2}}{4}$
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