Gujarat BoardEnglish MediumSTD 9MathsNumber Systems1 Mark
Question
Simplify the following: $4\sqrt{28}\div3\sqrt{7}\div\sqrt[3]{7}$
✓
Answer
$4\sqrt{28}\div3\sqrt{7}\div\sqrt[3]{7}$
$=4\sqrt{2\times2\times7}\times\frac{1}{3\sqrt{7}}\div\sqrt[3]{7}$
$=\frac{8\sqrt{7}}{3\sqrt{7}}\div\sqrt[3]{7}=\frac{8}{3}\div\sqrt[3]{7}$
We know that, the cube root of $7$ is $1.9129$ and
$\therefore\frac{8}{3}\div\sqrt[3]{7}=2.666\div1.9129$
$\Rightarrow\ 1.3936.$
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