Question
Simplify the following:
$\frac{7.83\times7.83-1.17\times1.17}{6.66}$

Answer

We have,
$\frac{7.83\times7.83-1.17\times1.17}{6.66}$
$=\frac{(7.83+1.17)(7.83-1.17)}{6.66}$ $\big[\because(\text{a}-\text{b})^2=(\text{a}+\text{b})(\text{a}-\text{b})\big]$
$=\frac{(9.00)(6.66)}{6.66}=9$
$\therefore\frac{7.83\times7.83-1.17\times1.17}{6.66}=9$

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