Question
Simplify the following: $\sqrt[4]{81}–8\sqrt[3]{216}+15\sqrt[5]{32}+\sqrt{225}$

Answer

$\sqrt[4]{81}–8\sqrt[3]{216}+15\sqrt[5]{32}+\sqrt{225}$ $=\sqrt[4]{3}^4–8\sqrt[3]{6^3}+15\sqrt[5]{2^5}+\sqrt{225}$ $=3-(8\times6)+(15\times2)+15$ $=3-48+30+15=0$

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