Question
Simplify the following:$\frac{3^{x+1}+3^x}{3^{x+3}-3^{x+1}}$
✓
Answer
$ \frac{3^{x+1}+3^x}{3^{x+3}-3^{x+1}}$
$= \frac{3^x(3+1)}{3^x\left(3^3-3\right)}$
$= \frac{4}{27-3}$
$= \frac{4}{24}$
$= \frac{1}{6} .$
$= \frac{3^x(3+1)}{3^x\left(3^3-3\right)}$
$= \frac{4}{27-3}$
$= \frac{4}{24}$
$= \frac{1}{6} .$
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