Question
Simplify:$(2x + y)(4x^2 - 2xy + y^2)$
✓
Answer
$(2x + y)(4x^2 - 2xy + y^2)$
$= 2x(4x^2 - 2xy + y^2) + y(4x^2 - 2xy + y^2)$
$= 8x^3 - 4x^2y + 2xy^2 + 4x^2y - 2xy^2 + y2$
$= 8x^3 + y^3.$
$= 2x(4x^2 - 2xy + y^2) + y(4x^2 - 2xy + y^2)$
$= 8x^3 - 4x^2y + 2xy^2 + 4x^2y - 2xy^2 + y2$
$= 8x^3 + y^3.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In a parallelogram $\text{ABCD}, E$ and $F$ are the midpoints of the sides $AB$ and $CD$ respectively. The line segments $AF$ and $BF$ meet the line segments $DE$ and $CE$ at points $G$ and $H$ respectively Prove that$: \triangle GEA \cong \triangle GFD$
→Simplify:$(a + b)^3 + (a - b)^3$
→Evaluate $:\log_{0.5}16$
→→
Rationalise the denominator of each:-
$\frac{\sqrt{2}}{\sqrt{2}+\sqrt{3}-\sqrt{5}}$
→$\frac{\sqrt{2}}{\sqrt{2}+\sqrt{3}-\sqrt{5}}$
Simplify $:\left(8 x^3 \div 125 y^3\right)^{\frac{2}{3}}$
→Solve $:x+ y = 7xy,2x - 3y = - xy$
→Solve the equation:
$4 x+\frac{x-y}{8}=17, x+2 y=\frac{y-2}{3}-2$
→$4 x+\frac{x-y}{8}=17, x+2 y=\frac{y-2}{3}-2$
The mean age of a group of 40 students is 17.45 years. Find the missing frequencies.
| Age (in years) | 15 | 16 | 17 | 18 | 19 | 20 |
| Number of students | 3 | ? | 9 | 11 | ? | 3 |
In the adjoining figure, ABCD is a trapezium in which $AB \| DC$. If M and N are the mid-points of AC and BD respectively, prove that $MN =\frac{1}{2}( AB - CD )$.
→