Question
Simplify:
3x − [5y − {6y + 2 (10y − x)}]
3x − [5y − {6y + 2 (10y − x)}]
✓
Answer
3x − [5y − {6y + 2 (10y − x)}]
= 3x − [5y − {6y + 20y − 2x}]
= 3x − [5y − 6y − 20y + 2x]
= 3x − 5y + 6y + 20y − 2x
= 3x − 2x + 6y + 20y − 5y
= x + 21y
= 3x − [5y − {6y + 20y − 2x}]
= 3x − [5y − 6y − 20y + 2x]
= 3x − 5y + 6y + 20y − 2x
= 3x − 2x + 6y + 20y − 5y
= x + 21y
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