Question
Simplify:
$4+3 \frac{1}{8}-3 \frac{1}{6}$

Answer

$4+3 \frac{1}{8}-3 \frac{1}{6} $
$=\frac{4}{1}+\frac{25}{8}-\frac{19}{6} $
$=\frac{4 \times 24}{1 \times 24}+\frac{25 \times 3}{8 \times 3}-\frac{19 \times 4}{6 \times 4} \ldots \ldots \ldots .(\text { LCM of } 8,6,=24) $
$=\frac{96}{24}+\frac{75}{24}-\frac{76}{24} $
$=\frac{95+75-76}{24}=\frac{95}{24}=3 \frac{23}{24}$

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