Question
Simplify
$\frac{n^2-9}{(n+3) !}+\frac{6}{(n+2) !}-\frac{1}{(n+1) !}$
$\frac{n^2-9}{(n+3) !}+\frac{6}{(n+2) !}-\frac{1}{(n+1) !}$
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