MCQ
Simplify:
$\frac{\sqrt3+\sqrt2}{\sqrt3-\sqrt2}+\frac{\sqrt3-\sqrt2}{\sqrt3+\sqrt2}$
  • A
    $4\sqrt6$
  • $10$
  • C
    $2$
  • D
    $\frac{4\sqrt6}{5}$

Answer

Correct option: B.
$10$

$\frac{\sqrt3+\sqrt2}{\sqrt3-\sqrt2}+\frac{\sqrt3-\sqrt2}{\sqrt3+\sqrt2}$
$=\frac{\big(\sqrt3+\sqrt2\big)^2+\big(\sqrt3-\sqrt2\big)^2}{3-2}$
$=\frac{3+2+3+2}{1}=10$

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