Gujarat BoardEnglish MediumSTD 6MATHSFractions3 Marks
Question
Simplity the following to its lowest term: $\frac{162}{108}$
✓
Answer
$\frac{162}{108}$ Factors of 162 are $1, 2, 3, 6, 9, 18, 27, 54, 81$ and $162$
Factors of $108$ are $108, 1, 2, 3, 4, 6, 9, 12, 18, 27$ and $54$
Common factor of $162$ and $108$ are $1, 2, 3, 6, 9, 18, 27, 54$ $HCF$ of $162$ and $108$ is $= 54$
Dividing both the numerator and denominator by $54,$
we get: $\frac{162\div54}{108\div54}=\frac{3}{2}$
Therefore, the simplest form obtained is, $\frac{162}{108}=\frac{3}{2}$
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