MCQ
$\sin ^{-1} x-\cos ^{-1} x=\frac{\pi}{6}$, then $x=$
  • A
    $\frac{1}{2}$
  • $\frac{\sqrt{3}}{2}$
  • C
    $-\frac{1}{2}$
  • D
    $-\frac{\sqrt{3}}{2}$

Answer

Correct option: B.
$\frac{\sqrt{3}}{2}$
$\frac{\sqrt{3}}{2}$

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