MCQ
$\sin {163^o}\cos {347^o} + \sin {73^o}\sin {167^o} = $
- A$0$
- ✓$1/2$
- C$1$
- DNone of these
$ = \sin ({180^o} - {17^o})\cos ({360^o} - {13^o}) + \cos ({90^o} - {17^o}) \sin ({180^o} - {13^o})$
$ = \sin {17^o}\cos {13^o} + \cos {17^o}\sin {13^o}$
$ =\sin {30^o} = 1/2$.
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