MCQ
$\sin 18^{\circ}=?$
- A$\frac{(\sqrt{3}+1)}{2}$
- B$\frac{(\sqrt{3}-1)}{2}$
- C$\frac{(\sqrt{5}+1)}{4}$
- D$\frac{(\sqrt{5}-1)}{4}$
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where $A = {\sin ^2}\alpha - \sin \alpha + \frac{1}{4}$
and $B = {\tan ^2}\alpha + \frac{2}{{\sqrt 3 }}\tan \alpha + \frac{1}{3}$ , then the number of value $(s)$ of $\alpha $ in $\left[ { - \frac{{3\pi }}{2},2\pi } \right]$ is - (where $sgnx$ denotes signum function of $x$ )