18^ =? - Vidyadip

MCQ

$\sin 18^{\circ}=?$

A
$\frac{(\sqrt{3}+1)}{2}$
B
$\frac{(\sqrt{3}-1)}{2}$
C
$\frac{(\sqrt{5}+1)}{4}$
D
$\frac{(\sqrt{5}-1)}{4}$

✓

Answer

(d) $\frac{(\sqrt{5}-1)}{4}$
Explanation: Remember $\sin 18^{\circ}=\frac{(\sqrt{5}-1)}{4}$

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