Question
$ \sin^{-1}\text{⁡x}+\cos^{1}\text{⁡x}= $
  1. $ \frac{π}{2}$
  2. π
  3. π3

Answer

  1. $ \frac{π}{2}$
solution:
$ \sin-1\text{⁡x}+\cos-1\text{⁡x}=π2; \text{x} ∈ [-1,1] $

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Given that $\left[\begin{array}{ll}1 & x\end{array}\right]\left[\begin{array}{cc}4 & 0 \\ -2 & 0\end{array}\right]=0$, the value of $x$ is :
Choose the correct answer from the given four options.
The area of the quadrilateral ABCD, where A(0, 4, 1), B(2, 3, -1), C(4, 5, 0) and D(2, 6, 2), is equal to:
The corner points of the feasible region determined by the system of linear inequalities are (0, 0), (4, 0), (2, 4) and (0, 5). If the maximum value of z = ax + by, where a, b > 0 occurs at both (2, 4) and (4, 0), then:
  1. a = 2b
  2. 2a = b
  3. a = b
  4. 3a = b
The points (k − 1, k + 2), (k, k + 1), (k + 1, k) are collinear for:
For any square matrix $A, A+A^{\prime}$ will be :
If $A=\left[\begin{array}{cc}\sin ^2 \theta & \sec ^2 \theta \\ \operatorname{cosec}^2 \theta & \frac{1}{2}\end{array}\right]$ and $B=\left[\begin{array}{cc}\cos ^2 \theta & -\tan ^2 \theta \\ -\cot ^2 \theta & \frac{1}{2}\end{array}\right]$ the value of $A + B$ will be :
$Q^+$ is the set of all positive rational numbers with the binary operation $*$ defined by $\text{a}*\text{b}=\frac{\text{ab}}2\ \forall\text{ a, b}\in\text{Q}^+$. The inverse of an element $\text{a}\in\text{Q}^+$ is:
The construction company uses concrete blocks made up of cement and sand. The weight of a concrete block has to be at least $5 kg$. Cement costs ₹ 20 per kg, while sand costs ₹ 6 per kg. Strength considerations dictate that the concrete block should contain minimum $4 kg$ of cement and not more than $2 kg$ of sand. Formulate the L.P.P for the cost to be minimum.
If $y=\cos ^{-1}\left(e^x\right)$, then $\frac{d y}{d x}$ is :
The value of $\int\limits^1_0\tan^{-1}\Big(\frac{2\text{x}-1}{1+\text{x}-\text{x}^2}\Big)\text{ dx},$ is:
  1. 1
  2. 0
  3. -1
  4. $\frac{\pi}{4}$